7. Ubahlah perbandingan suhu berikut ini a. 28° C = ....R b. ..K-122 F
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Penjelasan dengan langkah-langkah:
a. 28° C = 4/5 x 28
28°C = 112/5
28°C = 22,4°R
b. 122°F = (122 – 32)/9 x 5
122°F = 90/9 x 5
122°F = 10 x 5
122°F = 50°C
122°F = 50 + 273
122°F = 323 K
°R = 4/5 ( °C )
°R = 4/5 ( 28 )
[tex]^{0} r = \frac{4 \times 28}{5} [/tex]
[tex]^{0}r = \frac{112}{5} [/tex]
[tex]^{\circ}r = 22,4 ^{\circ} r[/tex]
_____________________
212°F = ( °F - 32 )/9 × 5
212°F = ( 212 - 32 )/9 × 5
[tex]212^{\circ}f = \frac{90}{9} \times 5[/tex]
[tex]212^{\circ}f = 10 \times 5 [/tex]
[tex]212^{\circ}f = 50^{circ} c[/tex]
[tex]212^{\circ}f = 50 + 273 [/tex]
[tex] 212^{\circ}f = 323 K [/tex]
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